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In a circle, two chords AB and CD intersect each other internally at point P. If AB = 16 cm. PB =6cm and PD =12 cm. then the value of PC (in cm) is eq
Question

In a circle, two chords AB and CD intersect each other internally at point P. If AB = 16 cm. PB =6cm and PD =12 cm. then the value of PC (in cm) is equal to

A.

3

B.

8

C.

6

D.

5

Correct option is D

Given:
AB = 16 cm
PB = 6 cm
PD = 12 cm
Solution:
We know that when two chords intersect each other internally, the following property holds:
AP
× PB = CP ×PD

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