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If y is the length of the median of an equilateral triangle, then find its area.
Question

If y is the length of the median of an equilateral triangle, then find its area.

A.

3y4 \frac{\sqrt{3}y}{4} \quad​​

B.

2y 2y \quad​​

C.

y23\frac{y^2}{\sqrt{3}} \quad​​

D.

3y \sqrt{3}y

Correct option is C

Given:

y is the length of the median of an equilateral triangle.

Formula used:

Area of an equilateral triangle =34×side2 \frac{\sqrt{3}}{4} \times \text{side}^2​​

Relation between the median (y) and the side (s) of an equilateral triangle:

y = (32)×s\left(\frac{\sqrt{3}}{2}\right) \times s

Solution:

From the relation between median and side:

y=(32)×s s=2y3y = \left(\frac{\sqrt{3}}{2}\right) \times s \implies s = \frac{2y}{\sqrt{3}}

Area=(34)×s2\text{Area} = \left(\frac{\sqrt{3}}{4}\right) \times s^2

Substituting s =2y3 \frac{2y}{\sqrt{3}}​ gives:

Area=(34)×(2y3)2 \left(\frac{\sqrt{3}}{4}\right) \times \left(\frac{2y}{\sqrt{3}}\right)^2

Area= (34)×(4y23)\left(\frac{\sqrt{3}}{4}\right) \times \left(\frac{4y^2}{3}\right)

Area =3×4y23×4=y23= \frac{\sqrt{3} \times 4y^2}{3 \times 4} = \frac{y^2}{\sqrt{3}}

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