If $$\frac{x}{49}=\frac{196}{x}$$​, find the value of $$'x'$$​.

The value of $$\sqrt{324}+\sqrt{0.0324}-\sqrt{8.41}\text{ is } \_\_\_\_\_\_.$$​ 

Evaluate 74².​

Simplify the expression: $$\sqrt{(9 + 4\sqrt{5})}$$​​

27³ + 10³ – 29³ + 246 is equal to:

The value of √400 + √0.0225 – √9 is __________.

The value of √(144 ) + √0.0225 - √9 =

The value of $$\sqrt{256} + \sqrt{0.0256} - \sqrt{4.41}$$​ is _________.

Which is greater: √45 or √49 – 1 ?

What value will come in place of question mark (?) in the following question?
​$$\left(9^2 \times 23 + 7^3 \times 8 + ?\right){\frac{1}{2}} = 87$$​​

​$$\frac{\sqrt[3]{1331}}{\sqrt[4]{10000}} \times \frac{5}{33} \times 30 =$$