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    If x : y = 4:3, then find the value of x2+y2x2−y2\frac{x^2 + y^2}{x^2 - y^2}x2−y2x2+y2​​
    Question



    If x : y = 4:3, then find the value of x2+y2x2y2\frac{x^2 + y^2}{x^2 - y^2}

    A.

    25:7

    B.

    21:11

    C.

    27:5

    D.

    17:13

    Correct option is A

    Given:x:y=4:3=>x=4k,y=3kNow, compute the required ratio:x2+y2x2y2=(4k)2+(3k)2(4k)2(3k)2=16k2+9k216k29k2=25k27k2=257(x2+y2):(x2y2)=25:7\textbf{Given:} \quad x : y = 4 : 3 \\\Rightarrow x = 4k, \quad y = 3k \\[10pt]\text{Now, compute the required ratio:} \\\frac{x^2 + y^2}{x^2 - y^2}= \frac{(4k)^2 + (3k)^2}{(4k)^2 - (3k)^2}= \frac{16k^2 + 9k^2}{16k^2 - 9k^2}= \frac{25k^2}{7k^2}= \frac{25}{7} \\[10pt]\therefore (x^2 + y^2) : (x^2 - y^2) = \boxed{25 : 7}​​

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