If $$x= (\sqrt{2352} \div \sqrt{1200}) \div \sqrt{0.04}$$​, then the value of $$\frac{x+1}{x-1}$$​ is:

Correct option is B

Given:

​$$x= (\sqrt{2352} \div \sqrt{1200}) \div \sqrt{0.04}$$​​

Solution:

​$$x= (\sqrt{2352} \div \sqrt{1200}) \div \sqrt{0.04}$$​​

​$$x= (28\sqrt{3} \div 20\sqrt{3}) \div (0.2)$$​​

​$$x= \left(\frac{28\sqrt{3}}{20\sqrt{3}}\right) \div (0.2)$$​​

​$$x= \frac{7}{5} \times \frac{1}{0.2}$$​​

x = 7

The value of  $$\frac{x+1}{x-1} =\frac{7+1}{7-1} =\frac{8}{6}$$​​

​$$= \frac{4}{3}$$​​