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If x = (1125×405)729\frac{(\sqrt{1125}×\sqrt{405})}{\sqrt{729}}729​(1125​×405​)​​ , then the value of x\sqrt{x}x​​ is:
Question

If x = (1125×405)729\frac{(\sqrt{1125}×\sqrt{405})}{\sqrt{729}}​ , then the value of x\sqrt{x}​ is:

A.

9

B.

3

C.

5

D.

25

Correct option is C

Given: 

x = (1125×405)729\frac{(\sqrt{1125}×\sqrt{405})}{\sqrt{729}}

Solution: 

(1125×405)729\frac{(\sqrt{1125}×\sqrt{405})}{\sqrt{729}} 

(3×3×5×5×5×3×3×3×3×5)3×3×3×3×3×3\frac{(\sqrt{3\times3\times5\times5\times5}×\sqrt{3\times3\times3\times3\times5})}{\sqrt{3\times3\times3\times3\times3\times3}} 

(155×95)27\frac{(15\sqrt{5}×9\sqrt{5})}{27} 

(155×5)3\frac{(15\sqrt{5}×\sqrt{5})}{3} 

(5×5)(5×5)

x = 25 

Then, 

x=25\sqrt{x} = \sqrt{25} 

x\sqrt{x} = 5​

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