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    If x = (1125×405)729\frac{(\sqrt{1125}×\sqrt{405})}{\sqrt{729}}729​(1125​×405​)​​ , then the value of x\sqrt{x}x​​ is:
    Question

    If x = (1125×405)729\frac{(\sqrt{1125}×\sqrt{405})}{\sqrt{729}}​ , then the value of x\sqrt{x}​ is:

    A.

    9

    B.

    3

    C.

    5

    D.

    25

    Correct option is C

    Given: 

    x = (1125×405)729\frac{(\sqrt{1125}×\sqrt{405})}{\sqrt{729}}

    Solution: 

    (1125×405)729\frac{(\sqrt{1125}×\sqrt{405})}{\sqrt{729}} 

    (3×3×5×5×5×3×3×3×3×5)3×3×3×3×3×3\frac{(\sqrt{3\times3\times5\times5\times5}×\sqrt{3\times3\times3\times3\times5})}{\sqrt{3\times3\times3\times3\times3\times3}} 

    (155×95)27\frac{(15\sqrt{5}×9\sqrt{5})}{27} 

    (155×5)3\frac{(15\sqrt{5}×\sqrt{5})}{3} 

    (5×5)(5×5)

    x = 25 

    Then, 

    x=25\sqrt{x} = \sqrt{25} 

    x\sqrt{x} = 5​

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