Correct option is AIf the transmission voltage of a line increases then the volume of the conductor material required decreases.v=P2ρℓ2V2cos2ϕWv∝1V2Where,v=volume of materialV=Transmission voltagev = \frac{P^2 \rho \ell^2}{V^2 \cos^2 \phi W} \\\boxed{v \propto \frac{1}{V^2}} \\\text{Where,} \\v = \text{volume of material} \\V = \text{Transmission voltage}v=V2cos2ϕWP2ρℓ2v∝V21Where,v=volume of materialV=Transmission voltage