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If the ratio of two numbers is 17 : 7 and the product of their LCM and their HCF is 119, then the sum of the reciprocals of the LCM and the HCF i
Question

If the ratio of two numbers is 17 : 7 and the product of their LCM and their HCF is 119, then the sum of the reciprocals of the LCM and the HCF is:

A.

120119\frac{120}{119}​​

B.

120137\frac{120}{137}​​

C.

120161\frac{120}{161}​​

D.

120139\frac{120}{139}

Correct option is A

Given:

Ratio of two numbers = 17: 7

Product of their LCM and HCF = 119

Formula Used:

If numbers are ax and bx with gcd(a,b) = 1, then
HCF = x, LCM = abx, and LCM×HCF=abx2 \text{LCM}\times \text{HCF} = abx^2​​

Solution:

Let numbers be 17x and 7x ((17,7) are coprime).

Then
LCM×HCF=(119x)×x=119x2=119\text{LCM}\times \text{HCF}= (119x)\times x=119x^2=119​​
x2=1 x=1.x^2=1 \implies x=1.​​
Hence HCF = 1, LCM = 119.

Sum of reciprocals:
1119+11=1+1119\frac{1}{119}+\frac{1}{1}=1+\frac{1}{119}​​

=120119.\frac{120}{119}.​​
​​​

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