​If the pressure of a gas is increased by two-fold at a constant volume, the work done by the gas will be _____.

Correct option is A

The correct answer is (a) zero

Explanation:

In thermodynamics, work done by a gas (W) is given by the formula:

                                              $$W = P \Delta V$$​​

Where:

• P = Pressure
• ​$$\Delta V$$​ = Change in volume

If the volume is constant (i.e., $$\Delta V = 0$$​), then:

                   $$W = P \times 0 = 0$$​​

So, even if the pressure is doubled, as long as the volume does not change, the work done remains zero.

Information Booster:

• Isobaric process: Pressure is constant, volume changes → Work is done.
• Isochoric process (also called isovolumetric): Volume is constant → No work is done.
• Isothermal process: Temperature is constant.
• Adiabatic process: No heat exchange with surroundings.

In an isochoric (constant volume) process, pressure and temperature may change, but no mechanical work is done since the piston or container doesn't expand or contract.