Formula Used:
The nth term of AP | an= a + (n – 1) × d |
Solution:
Numbers = 2 ,4 ,6,8,….…………….26
In descending order= 26 , 24 ,22,20,……………….4,2
The number which will at the 9th place from the bottom
9thterm= a+ (n-1 )d
= 2+ (9-1)×2
= 2+16
= 18
English
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90 Mins English English100 Questions100 Marks90 Mins English English40 Questions30 Marks25 Mins EnglishThe geometric mean of squares of two positive integers is 10. The smallest possible sum of these two integers is
In an arithmetic progression (AP), the 9th term is 5 times the 2nd term and the 8th termis 1 more than 10 times the first term. What is the 4th term of the geometricprogression (GP) whose first term is the second term of AP and whose common ratiois equal to the common difference of AP?
If then is equal to:
If the ratio of the term of an AP to its term is 2 : 3, find the ratio of the sum of its first five terms to the sum of its first 10 terms
The value of 1 + 2 + 3 + ... + 30 + 31 + 30 + 29+...+3 + 2 + 1 = ?
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