If the length of the diagonals of a rhombus are 12 cm and 16 cm, then the area of the rhombus will be:

Given:
​$$d_1 = 12 \text{ cm},\quad d_2 = 16 \text{ cm}\\[6pt]$$​​
Area of a rhombus $$= \frac{1}{2} \times d_1 \times d_2\\[6pt]$$​​
Area $$= \frac{1}{2} \times 12 \times 16\\[6pt]$$​​
Area $$= \frac{1}{2} \times 192\\[6pt]$$​​
Area $$= 96 \text{ cm}^2$$
Correct answer is (d)