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If the first term of a geometric progression is 2 and the common ratio is 3, then what will be the fifth term of the geometric progression?
Question

If the first term of a geometric progression is 2 and the common ratio is 3, then what will be the fifth term of the geometric progression?

A.

243

B.

324

C.

81

D.

162

Correct option is D

Given:

First term (a) = 2
Common ratio (r) = 3

Formula Used:
The n-th term of a geometric progression is given by the formula:

Tn=a×rn1T_n = a \times r^{n-1}​​

Where:

TnT_n is the n-th term,

a is the first term,

r is the common ratio, and

n is the term number.

Solution:
For the fifth term (n = 5):

T5=2×351=2×34T_5 = 2 \times 3^{5-1} = 2 \times 3^4​​

T5=2×81=162T_5 = 2 \times 81 = 162​​

The fifth term of the geometric progression is 162.

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