If the first term of a geometric progression is 2 and the common ratio is 3, then what will be the fifth term of the geometric progression?

Correct option is D

Given:

First term (a) = 2
Common ratio (r) = 3

Formula Used:
The n-th term of a geometric progression is given by the formula:

​$$T_n = a \times r^{n-1}$$​​

Where:

​$$T_n$$ is the n-th term,

a is the first term,

r is the common ratio, and

n is the term number.

Solution:
For the fifth term (n = 5):

​$$T_5 = 2 \times 3^{5-1} = 2 \times 3^4$$​​

​$$T_5 = 2 \times 81 = 162$$​​

The fifth term of the geometric progression is 162.