If P is 9 times more than Q, then Q is what percentage less than P?

Correct option is B

Given:

P is 9 times more than Q, which means:

We have to find what percentage less QQ is than PP.

Formula Used:

​$$\text{Percentage less} = \frac{P - Q}{P} \times 100$$​​

Solution:

P = Q + 9Q = 10Q

So, P = 10Q

Substitute P = 10Q into the formula:

​$$\text{Percentage less} = \frac{10Q - Q}{10Q} \times 100 = \frac{9Q}{10Q} \times 100$$​​

​$$\text{Percentage less} = \frac{9}{10} \times 100 = 90\%$$​​

Q is 90 percent less than P. 

Thus,  the correct option is (b) 90%