If one angle of parallelogram is $$48^0$$ less than twice the smallest angle, then the measure of the largest angle of the parallelogram will be:​

Correct option is A

Given:

One angle of a parallelogram is $$48^\circ$$​ less than twice the smallest angle.

Concept used:

In a parallelogram, opposite angles are equal and the sum of the adjacent angles is $$180^\circ$$

Solution:

The smallest angle of the parallelogram as $$x^\circ$$

​​The other angle is - $$2x-48^\circ$$

​​the sum of the smallest angle x and the given angle $$2x-48^\circ$$ should be $$180^\circ$$ 

x + $$(2x−48^\circ)$$ = $$180^\circ$$ 

$$3−48^\circ=180^\circ$$ 

$$3x = 228^\circ$$ 

x = $$76^\circ$$ 

The measure of the given angle is: 

​$$2x−48^\circ=2(76^\circ)−48^\circ=152^\circ−48^\circ=104^\circ$$ 

​The measure of the largest angle of the parallelogram is $$104^\circ$$ 

Thus, correct answer is (a) $$104^\circ$$​​