If 'N' is the greatest four digit number which when divided by 27, 6, 8 and 9 leaves in each case the same remainder of 5, then the sum of the digits of 'N' is

Correct option is C

Given:

If 'N' is the greatest four digit number which when divided by 27, 6, 8 and 9 leaves

in each case the same remainder of 5, then the sum of the digits of 'N'

Solution:

LCM of 27, 6, 8, and 9 = 216

Greatest number of 4 digits = 9999
Dividing the largest four-digit number by the LCM of the given numbers
Remainder = 63
Largest divisible number of 4 digits by 216 (27, 6, 8, 9) = 9999 - 63 = 9936
Divided by 27, 6, 8, and 9 leaves remainder 5 = 9936 + 5 = 9941
Now the sum of digits = 9 + 9 + 4 + 1 = 23