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    If '+ 'means '÷ ', '- ' means ' +', ' ×' means '-', ‘÷’ means ‘×', what will be the value of the following expression?[{(12-2)×(3÷2)}+(12×4)]
    Question

    If '+ 'means '÷ ', '- ' means ' +', ' ×' means '-', ‘÷’ means ‘×', what will be the value of the following expression?
    [{(12-2)×(3÷2)}+(12×4)]

    A.

    4

    B.

    3

    C.

    1

    D.

    2

    Correct option is C

    Logic: interchange mathematical operators and solve as per BODMAS rule.
    Operation preference wiseSymbolBrackets[],,()Orders,of(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline Brackets &[],{}, () \\ \hline Orders, of & (power), √ (root) , of \\ \hline Division& ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\\hline \end{array}​​
    Given:
    [{(12-2)×(3÷2)}+(12×4)]
    After interchanging, '+ 'means '÷ ', '- ' means ' +', ' ×' means '-', ‘÷’ means ‘×', we get following equation - 
    [{(12 + 2) - (3 × 2)} ÷ (12 4)]
    =[{14 - 6} ÷ 8]
    =[8 ÷ 8]
    =1
    Thus, correct option (c).

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