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If (L)M\mathrm{(L)_M}(L)M​​ represents a number L in the base-M number system, then which of the following numbers are equivalent to (19)16(19)_{
Question

If (L)M\mathrm{(L)_M}​ represents a number L in the base-M number system, then which of the following numbers are equivalent to (19)16(19)_{16}​?
A. (11001)2(11001)_{2}​​
B. (201)3(201)_3​​
C. (121)4(121)_4​​
D. (101)5(101)_5​​
E. (25)10(25)_{10}​​
Choose the correct answer from the options given below: ​​

A.

A, C and E only

B.

B and D only

C.

A, B and D only

D.

A, B, C, D and E

Correct option is A

To solve the problem, we need to convert (19)16\bf{(19)_{16}}​ (a number in hexadecimal or base-16) into different bases and match it with the options given.
Step 1: Convert (19)16\bf{(19)_{16}}to decimal (base 10)
The number 19 in hexadecimal (base 16) can be converted to decimal by expanding the number using powers of 16:
(19)16=(1×161)+(9×160)(19)_{16} = (1 \times 16^1) + (9 \times 16^0)​​
=16+9=25= 16 + 9 = 25​​
So, (19)16\bf{(19)_{16}}​ is 25 in decimal.
Step 2: Check which of the options are equivalent to 25 in decimal:
A. (11001)2\bf{(11001)_2}(Binary)
To check if (11001)2\bf{(11001)_2}​ equals 25 in decimal, convert it to decimal:
(11001)2=(1×24)+(1×23)+(0×22)+(0×21)+(1×20)(11001)_2 = (1 \times 2^4) + (1 \times 2^3) + (0 \times 2^2) + (0 \times 2^1) + (1 \times 2^0)​​
=16+8+0+0+1=25= 16 + 8 + 0 + 0 + 1 = 25​​
So, (11001)2=25\bf{(11001)_2} = 25​ in decimal.
B. (201)3\bf{(201)_3}(Ternary)
To check if (201)3\bf{(201)_3}​ equals 25 in decimal, convert it to decimal:
(201)3=(2×32)+(0×31)+(1×30)(201)_3 = (2 \times 3^2) + (0 \times 3^1) + (1 \times 3^0)​​
=2×9+0×3+1×1= 2 \times 9 + 0 \times 3 + 1 \times 1​​
=18+0+1= 18 + 0 + 1​​
=19= 19​​
So, (201)325\bf{(201)_3} ≠ 25​ in decimal.
C. (121)4\bf{(121)_4}(Quaternary)
To check if (121)4\bf{(121)_4}​ equals 25 in decimal, convert it to decimal:
(121)4=(1×42)+(2×41)+(1×40)(121)_4 = (1 \times 4^2) + (2 \times 4^1) + (1 \times 4^0)​​
=1×16+2×4+1×1= 1 \times 16 + 2 \times 4 + 1 \times 1​​
=16+8+1= 16 + 8 + 1​​
=25= 25​​
So, (121)4=25\bf{(121)_4} = 25​ in decimal.
D. (101)5\bf{(101)_5} (Quinary)
To check if (101)5\bf{(101)_5}​ equals 25 in decimal, convert it to decimal:
(101)5=(1×52)+(0×51)+(1×50)(101)_5 = (1 \times 5^2) + (0 \times 5^1) + (1 \times 5^0)​​
=1×25+0×5+1×1= 1 \times 25 + 0 \times 5 + 1 \times 1​​
=25+0+1= 25 + 0 + 1​​
=26= 26​​
So, (101)525\bf{(101)_5} ≠ 25​ in decimal.
E. (25)10\bf{(25)_{10}}(Decimal)
This is already in decimal form, so (25)10=25\bf{(25)_{10}} = 25​.
Step 3: Conclusion
The numbers (11001)2,(121)4\bf{(11001)_2}, \bf{(121)_4}​ and (25)10\bf{(25)_{10}}​ are equivalent to (19)16\bf{(19)_{16}}​.
Thus, the correct answer is:
(a) A, C and E only.
Information Booster:
1. Binary (Base-2):
Uses digits 0 and 1, with each digit representing increasing powers of 2.
2. Ternary (Base-3): Uses digits 0, 1 and 2, with each digit representing increasing powers of 3.
3. Quaternary (Base-4): Uses digits 0 to 3, with each digit representing increasing powers of 4.
4. Quinary (Base-5): Uses digits 0 to 4, with each digit representing increasing powers of 5.

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