Correct option is B
Let, Im,n=2πi1∮Czmz−ndzwhere∣z∣=1
Option 1.
Let m ≥ n take m = n = 2 Then,
Im,n=2πi1∮Cz2z−2dz=2πi1∮c1dz=0=1
⟹Option 1 is incorrect.
Option 2.
Let m+1=n , Then
Im,n=2πi1∮Czn−1z−ndz=2πi1∮cz1dz=2πi12πi=1 ( Using cauchy integral formula)
⟹Option 2 is correct.