If distance between two point (x,- 1) and (3, 2) is 5 units then find the value of x

Correct option is D

Given:

Points: (x, -1) and (3, 2)

Distance between the points = 5 units

Formula Used:

​$$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$$​​

Where:

​$$(x_1, y_1) = (x, -1)$$​​

​$$(x_2, y_2) = (3, 2)$$​​

Solution:

​$$5 = \sqrt{(3 - x)^2 + (2 - (-1))^2}$$​​

​$$5 = \sqrt{(3 - x)^2 + 3^2}$$​​

​$$5 = \sqrt{(3 - x)^2 + 9}$$​​

​$$25 = (3 - x)^2 + 9$$​​

​$$16 = (3 - x)^2$$​​

​$$\pm 4 = 3 - x$$​​

$$x = -1 \quad \text{or} \quad x = 7$$​