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If at same rate of interest, in 2 years, the simple interest is Rs. 40 and compound interest is Rs. 45, then what is the principal (in Rs. )?
Question

If at same rate of interest, in 2 years, the simple interest is Rs. 40 and compound interest is Rs. 45, then what is the principal (in Rs. )?

A.

80

B.

84

C.

75

D.

73

Correct option is A

Given:

Time = 2 years

Simple Interest (SI) = Rs. 40

Compound Interest (CI) = Rs. 45

Difference = Rs. 5

We are to find the Principal (P)

Formula Used:

The difference between CI and SI for 2 years at same rate R% is:

CI - SI = P×R21002\frac{P \times R^2}{100^2}​​

Solution:

From the formula;

5=P×R210000(1)5 = \frac{P \times R^2}{10000} \quad \text{(1)}​​

Also,

SI = P×R×2100=40(2)\frac{P \times R \times 2}{100} = 40 \quad \text{(2)}​​

From (2):

2PR100=40 PR=2000(3)\frac{2PR}{100} = 40\\ \ \\ PR = 2000 \quad \text{(3)}​​

Substitute PR from (3) into (1):

From (1):

5=P×R210000 5=(PR)×R10000 5=2000×R10000 5=R5 =>R=255 = \frac{P \times R^2}{10000} \\ \ \\5 = \frac{(PR) \times R}{10000} \\ \ \\5= \frac{2000 \times R}{10000}\\ \ \\ 5 = \frac{R}{5} \\ \ \\ \Rightarrow R = 25​​

Now substitute back into (3):

PR=2000 P=200025=Rs. 80PR = 2000\implies P = \frac{2000}{25} = Rs. \ 80 

Alternate Method:

For 2 years,

CISI=SI×r100\text{CI} - \text{SI} = \frac{\text{SI} \times r}{100}​​

5 = 40×r100\frac{40 \times r}{100}​​
r = 25%

P =40×10025×2= \frac{40 \times 100}{25 \times 2} = ​80

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