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​If at same rate of interest, in 2 years, the simple interest is ₹60 and compound interest is ₹66, then what is the principal (in ₹)?
Question

​If at same rate of interest, in 2 years, the simple interest is ₹60 and compound interest is ₹66, then what is the principal (in ₹)?

A.

143

B.

150

C.

145

D.

154

Correct option is B

Given:

Interest in simple interest for 2 years = ₹60

Interest in compound interest for 2 years = ₹66

Time =1.5 years

Formula Used:

SI=P×R×T100SI = \frac{P\times R\times T}{100}​​

Compounded Amount =Principle×(1+r100)t Principle \times \left(1+ \frac{r}{100}\right)^{t} 

CI - SI = P(R100)2P\left(\frac{R}{100}\right)^2​​​

Compound Interest = Amount - Principle

Solution:

Interest in simple interest is same every year hence simple interest for one year = 602 \frac{60}{2} = ₹30

Now the compound interest more is only the interest on the interest in first year

Hence, 66-60 = ₹6 is the interest on ₹30

Percent of 6 of 30 = 630×100\frac{6}{30} \times 100 = 20%

Let the principle sum be x

Then 20% of x = 30

x=10020×30 \frac{100}{20} \times 30 = ₹150 

Alternate Solution:

Using the direct formula:

6=P(R100)2 60000=PR2 Substitute (R=P3000): 60000=P(P3000)2 60000=PP29,000,000 60000=P39,000,000 P3=60000×9,000,000 P=60,0009,000,000=1506 = P\left(\frac{R}{100}\right)^2 \\ \ \\60000 = PR^2 \\ \ \\Substitute\ ( R = \frac{P}{3000} ): \\ \ \\60000 = P \left(\frac{P}{3000}\right)^2 \\ \ \\60000 = P \cdot \frac{P^2}{9,000,000} \\ \ \\60000 = \frac{P^3}{9,000,000}\\ \ \\P^3 = 60000 \times 9,000,000\\ \ \\P = \frac{60,000}{9,000,000} = ₹150​​

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