If angles A,B,C and D of a quadrilateral ABCD, taken in order, are in the ratio 3:7:6:4, then ABCD is a:

Correct option is C

Given:

Angles of a quadrilateral are in ratio = 3:7:6:4 respectively

Formula Used:

Sum of angles of a quadrilateral = $$360^o$$​​

Solution:

Let the angles be 3x,7x,6x and 4x respectively

Then 3x+7x+6x+4x = 360

​$$20x=360^o$$​​

x=18$$^o$$​​

Angles are:

A=3x = 54$$^o$$​​

B=7x =126$$^o$$​​

C=6x =108$$^o$$​​

D=4x=72$$^o$$​​

A+B = $$54^o+ 126^o = 180^o$$​​

C+D =$$108^o + 72^o = 180^o$$​​

In  kites, rhombus and parallelogram opposite angles are equal

Hence it is a trapezium