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If α and β are the zeroes of the polynomial x2+x+1x^2+x+1x2+x+1​ then the value of 1α+1β\frac{1}{α}+\frac{1}{β}α1​+β1​​ will be:
Question

If α and β are the zeroes of the polynomial x2+x+1x^2+x+1​ then the value of 1α+1β\frac{1}{α}+\frac{1}{β}​ will be:

A.

0

B.

1

C.

-1

D.

None of these

Correct option is C

Given:

The polynomial equation is:

x2^2​ + x + 1 = 0

The sum and product of the roots (zeroes) α and β are

Sum of roots: α + β = ba=11-\frac{b}{a} = -\frac{1}{1}​ = -1

Product of roots: αβ = ca=11\frac{c}{a} = \frac{1}{1}​ = 1

1α+1β\frac{1}{\alpha} + \frac{1}{\beta}

Solution:

1α+1β=α+βαβ 1α+1β=11=1 1\frac{1}{\alpha} + \frac{1}{\beta} = \frac{\alpha + \beta}{\alpha \beta}\\ \ \\ \frac{1}{\alpha} + \frac{1}{\beta} = \frac{-1}{1} = -1\\ \ \\\boxed{-1}

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