If A1 is 19 times more than A2, then A2 is what percentage less than A1?

Correct option is B

Solution:
Let’s assume:
A₂ = x
Then, A1 is 19 times more than A2, which means:

​$$\text A_2 = x \\\text{Then } A_1 = x + 19x = 20x \\[10pt]\text{Percentage less of } A_2 \text{ compared to } A_1: \\\left( \frac{A_1 - A_2}{A_1} \right) \times 100 = \left( \frac{20x - x}{20x} \right) \times 100 \\\ \\= \left( \frac{19x}{20x} \right) \times 100 = 95\%$$

Final Answer: (B) 95 percent​​