If a satellite completes revolution in orbit two times a day, then angular velocity is

Correct option is C

The correct answer is (C) 720°/day

Explanation:
• Angular velocity is the rate at which an object rotates or revolves around an axis, or the change in angular position over time.
• A single complete revolution in a circular orbit corresponds to an angular displacement of 360 degrees (or $2π$ radians).
• If a satellite completes two full revolutions in one day, the total angular distance covered is: $2 \times 360^{\circ} = 720^{\circ}$.
• Therefore, the angular velocity per day is $720^{\circ}/day$.
• In physics, this is often expressed in radians per second ($ω = Δθ / Δt$), but the units used in the options are degrees per day.

Information Booster:
• For a geostationary satellite, which completes exactly one revolution per day to stay above the same spot on Earth, the angular velocity would be $360^{\circ}/day$.
• Higher orbital speeds (and thus higher angular velocities) are required for satellites in Lower Earth Orbit (LEO) compared to those in higher orbits.

Additional Knowledge:
• 180°/day (Option A): Corresponds to half a revolution per day.
• 360°/day (Option B): Corresponds to one revolution per day (characteristic of geostationary/geosynchronous satellites).
• 90°/day (Option D): Corresponds to a quarter of a revolution per day.