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If a memory has 10 address lines and the size of each addressable location (block) is 4 bytes, then what is the maximum storage capacity of the mem
Question

If a memory has 10 address lines and the size of each addressable location (block) is 4
bytes, then what is the maximum storage capacity of the memory?

A.

4 kilobyte

B.

2 kilobyte

C.

1 kilobyte

D.

3 kilobyte

Correct option is A

Step 1: Calculate the number of addressable locations The number of addressable locations in memory is determined by the number of address lines: Number of Locations =2Number of Address Lines  Given Number of Address Lines =10 : Number of Locations =210=1024 Step 2: Calculate the memory size Each addressable location (block) holds 4 bytes of data. Total Memory Size = Number of Locations × Block Size Substituting values: Total Memory Size =1024×4 bytes =4096 bytes Convert bytes to kilobytes:
Total Memory Size =4096/1024 = 4kilobytes (kB)

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