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    If a memory has 10 address lines and the size of each addressable location (block) is 4 bytes, then what is the maximum storage capacity of the mem
    Question

    If a memory has 10 address lines and the size of each addressable location (block) is 4
    bytes, then what is the maximum storage capacity of the memory?

    A.

    4 kilobyte

    B.

    2 kilobyte

    C.

    1 kilobyte

    D.

    3 kilobyte

    Correct option is A

    Step 1: Calculate the number of addressable locations The number of addressable locations in memory is determined by the number of address lines: Number of Locations =2Number of Address Lines  Given Number of Address Lines =10 : Number of Locations =210=1024 Step 2: Calculate the memory size Each addressable location (block) holds 4 bytes of data. Total Memory Size = Number of Locations × Block Size Substituting values: Total Memory Size =1024×4 bytes =4096 bytes Convert bytes to kilobytes:
    Total Memory Size =4096/1024 = 4kilobytes (kB)

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