If a:b::b:c, and b = 96, then which of the following can be a possible pair of values of a and c ?

Correct option is B

Given :
a : b :: b : c, and b = 96
Formula Used:
a/b = b/c
$$b^2$$​= ac
Solution:
$$b^2$$​ = ac
96 × 96 = ac
According to the question, only one option satisfies
the above equation where a = 32 , c = 288