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If a and b are of the same sign and (3a2−8b2):(a2+4b2)=2:1(3a^2-8b^2):(a^2+4b^2)= 2:1(3a2−8b2):(a2+4b2)=2:1​, then a : b = ?
Question

If a and b are of the same sign and (3a28b2):(a2+4b2)=2:1(3a^2-8b^2):(a^2+4b^2)= 2:1​, then a : b = ?

A.

5 : 4

B.

1 : 4

C.

4 : 5

D.

4 : 1

Correct option is D

Given:

(3a28b2):(a2+4b2)=2:1(3a^2 - 8b^2) : (a^2 + 4b^2) = 2 : 1

We need to find the value of a : b.

Solution:

3a28b2a2+4b2=21\frac{3a^2 - 8b^2}{a^2 + 4b^2} = \frac{2}{1}​​

3a28b2=2(a2+4b2)3a^2 - 8b^2 = 2(a^2 + 4b^2)

3a22a2=8b2+8b23a^2 - 2a^2 = 8b^2 + 8b^2

a2=16b2a^2 = 16b^2

a = 4b

Since a and b are of the same sign, we have:

a : b = 4 : 1

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