If 9 ÷ 5 + 3 × 7 = 22 and 4 ÷ 7 + 2 × 15 = 29, then find the value of 14 ÷ 5 + 35 × 9.

Correct option is D

Given:
9 ÷ 5 + 3 × 7 = 22
4 ÷ 7 + 2 × 15 = 29
14 ÷ 5 + 35 × 9 = ?
Let:

After interchanging the code sign we get following equations-
Bodmas table-

$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}$$​​
9 × 5 ÷ 3 + 7 = 22
9 × 5/3 + 7 = 22
15 + 7 = 22
22 = 22
And
4 × 7 ÷ 2 + 15 = 29
4 × 7/2 + 15 = 29
14 + 15 = 29
29 = 29
Similarly,
14 × 5 ÷ 35 + 9 = ?
14 × 1/7 + 9 = ?
2 + 9 = ?
? = 11
Correct answer is (d) 11.