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If 7(x) + 5, 7(x) + 4, 5(x) + 5 and y are in proportion when x = 5, find the value of y.
Question

If 7(x) + 5, 7(x) + 4, 5(x) + 5 and y are in proportion when x = 5, find the value of y.

A.

29

B.

29.5

C.

29.75

D.

29.25

Correct option is D

Given:

7(x) + 5, 7(x) + 4, 5(x) + 5 and y are in proportions

Formula Used:

If the numbers a,b,c and d are in proportions then:

a:b::c:d

a×d=b×ca \times d = b \times c​​

Solution:

Hence the 7(x) + 5, 7(x) + 4, 5(x) + 5 and y are in proportion

Putting the value of x =5

7(5) + 5: 7(5) + 4:: 5(5) + 5 : y

40:39::30 : y

Hence y =39×3040\frac{39 \times 30}{40}​ = 29.25

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