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    If 7(x) + 5, 7(x) + 4, 5(x) + 5 and y are in proportion when x = 5, find the value of y.
    Question

    If 7(x) + 5, 7(x) + 4, 5(x) + 5 and y are in proportion when x = 5, find the value of y.

    A.

    29

    B.

    29.5

    C.

    29.75

    D.

    29.25

    Correct option is D

    Given:

    7(x) + 5, 7(x) + 4, 5(x) + 5 and y are in proportions

    Formula Used:

    If the numbers a,b,c and d are in proportions then:

    a:b::c:d

    a×d=b×ca \times d = b \times c​​

    Solution:

    Hence the 7(x) + 5, 7(x) + 4, 5(x) + 5 and y are in proportion

    Putting the value of x =5

    7(5) + 5: 7(5) + 4:: 5(5) + 5 : y

    40:39::30 : y

    Hence y =39×3040\frac{39 \times 30}{40}​ = 29.25

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