If 60 @ 35 # 15 *6 = -65 and 40 @ 30 #6*7 = -32, then 90 @ 10 # 6 * 5 = ?

Given:
60 @ 35 # 15 *6 = -65
40 @ 30 #6*7 = -32
90 @ 10 # 6 * 5 = ?
In this question the logic is –
@ = -
# = -
* = ×
Bodmas table-
​$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline Brackets &[],{}, () \\ \hline Orders, of & (power), √ (root) , of \\ \hline Division& ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\\hline \end{array}$$​​
60 @ 35 # 15 *6 = -65 After interchanging the symbol with sign we get following equation –
60 - 35 - 15 × 6 = -65
60 - 35 - 90 = -65
60 - 125 = -65
-65 = -65
40 @ 30 #6*7 = -32 After interchanging the symbol with sign we get following equation –
40 - 30 – 6 × 7 = -32
40 - 30 –42 = -32
40 - 72 = -32
-32 = -32
Similarly,
90 - 10 - 6 × 5 = ?
90 - 10 - 30 = ?
90 - 40 = ?
? = 50
Correct answer is (d) 50.