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If 6 @ 10 # 5 * 7 = 63 and 4 @ 3 # 2 * 5 = 15, then 4 @ 5 # 6 * 7 =?
Question

If 6 @ 10 # 5 * 7 = 63 and 4 @ 3 # 2 * 5 = 15, then 4 @ 5 # 6 * 7 =?

A.

41

B.

28

C.

39

D.

18

Correct option is A

Logic: First output = (2nd × 3rd) + (1st + 4th)
First expression: 6 @ 10 # 5 * 7 = 63
Using the given logic:
2nd × 3rd = 10 × 5 = 50
1st + 4th = 6 + 7 = 13
Output = 50 + 13 = 63
This matches the given result.
Second expression: 4 @ 3 # 2 * 5 = 15
Using the same logic:
2nd × 3rd = 3 × 2 = 6
1st + 4th = 4 + 5 = 9
Output = 6 + 9 = 15
This matches the given result.
Now, solve the third expression: 4 @ 5 # 6 * 7 = ?
Using the same logic:
2nd × 3rd = 5 × 6 = 30
1st + 4th = 4 + 7 = 11
Output = 30 + 11 = 41
Correct Answer (a) 41.

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