If $$\sqrt{\smash[b]{484}\sqrt{\smash[b]{25÷x}}}$$​ = 22, then $$x$$​= ________.

Correct option is A

Given:

​$$\sqrt{\smash[b]{484}\sqrt{\smash[b]{25÷x}}}=22$$ 

Solution:

Square the both side of the equation:

=$$(\sqrt{\smash[b]{484}\sqrt{\smash[b]{25÷x}}})^2= (22)^2$$ 

= 484$$\sqrt{25÷x}$$ = 484

=$$\sqrt{25÷x}$$ = $$\frac{484}{484}=1$$

=$$\sqrt{25÷x}=1$$​​

Again square the both side of the equation:

​$$(\sqrt{25÷x})^2= (1)^2$$

= $${25÷x}$$ = 1

=$$\frac{x}{25}=1$$ 

$$x=25$$ 

Thus the correct option is (A)