If 40 A 10 B 8 C 15 = 65 and 15 A 30 B 9 C 20 = 70, then
7 A 9 B 3 C 8 = ?

Correct option is D

Given the logic where: A = multiply (×) B = divide (÷) C = addition (+) First Equation: 40 A 10 B 8 C 15 = 65 Substitute the operations: 40 × 10 ÷ 8 + 15 = 65 Solve step by step: 40 × 10 = 400 400 ÷ 8 = 50 50 + 15 = 65 The equation holds true.
Second Equation: 15 A 30 B 9 C 20 = 70 Substitute the operations: 15 × 30 ÷ 9 + 20 = 70 Solve step by step: 15 × 30 = 450 450 ÷ 9 = 50 50 + 20 = 70 The equation holds true.
Final Equation: 7 A 9 B 3 C 8 = ? Substitute the operations: 7 × 9 ÷ 3 + 8 = ? Solve step by step: 7 × 9 = 63 63 ÷ 3 = 21 21 + 8 = 29 Answer: (d) 29