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If 2x−3y=72x-3y=72x−3y=7​ and xx+y=56\frac{x}{x+y}=\frac{5}{6}x+yx​=65​​, then what is the value of x−yx-yx−y​?
Question

If 2x3y=72x-3y=7​ and xx+y=56\frac{x}{x+y}=\frac{5}{6}​, then what is the value of xyx-y​?

A.

4

B.

7

C.

6

D.

15\frac{1}{5}​​

Correct option is A

Given:

2x3y=7(i)xx+y=56(ii)2x - 3y = 7 \quad \text{(i)} \\ \dfrac{x}{x + y} = \dfrac{5}{6} \quad \text{(ii)}​​

We are to find the value of x - y.

Solution:

From equation (ii):

6x = 5(x + y)

6x = 5x + 5y

x = 5y ….(iii)

Substitute (iii) into equation (i):

2(5y) - 3y = 7

10y - 3y = 7

7y = 7

y = 1

Now, from (iii): x = 5y = 5

x - y = 5 - 1 = 4

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