If 2 is subtracted from each odd digit and 1 is added to each even digit in the number 83252769, how many digits will occur more than once in the new number thus formed?

Correct option is C

The given number is 83252769.

Subtract 2 from each odd digit.

Add 1 to each even digit.

The digits in the number are:

8, 3, 2, 5, 2, 7, 6, 9

Odd digits: 3, 5, 7, 9

Even digits: 8, 2, 2, 6

For odd digits:

3−2=1

5−2=3

7−2=5

9−2=7

For even digits:

8+1=9

2+1=3

2+1=3

6+1=7

After applying the operations, the new digits are: 9, 1, 3, 3, 3, 5, 7, 7

From the new number: 9, 1, 3, 3, 3, 5, 7, 7

3 occurs 3 times.

7 occurs 2 times.

So, the digits that occur more than once are 3 and 7.

Correct answer: 2 digits occur more than once.