If 2 is added to each odd digit and 1 is subtracted from each even digit in the number 23584617, how many digits will
appear more than once in the new number thus formed?

Correct option is A

Given a number: 23584617.
We are to:
Add 2 to each odd digit
Subtract 1 from each even digit
Then, determine how many digits appear more than once in the resulting number.
Step 1: Break down the digits
Digits in the number:
2, 3, 5, 8, 4, 6, 1, 7
Step 2: Apply the transformation
Even digits: 2, 8, 4, 6 → subtract 1
Odd digits: 3, 5, 1, 7 → add 2
So:
2 → 1
3 → 5
5 → 7
8 → 7
4 → 3
6 → 5
1 → 3
7 → 9
Step 3: Transformed number:
Digits after transformation:
1, 5, 7, 7, 3, 5, 3, 9
Step 4: Count frequencies
3 → 2 times
5 → 2 times
7 → 2 times
Step 5: Count digits that appear more than once
Digits: 3, 5, 7 → 3 digits
 Final Answer: A. Three