If 2 is added to each even digit and 1 is subtracted from each odd digit in the number 74135296, how many digits will appear more than once in the new number thus formed?​

Given: 74135296

Add 2 to each even digit and subtract 1 from each odd digit.

7 (odd) → 7 − 1 = 6

4 (even) → 4 + 2 = 6

1 (odd) → 1 − 1 = 0

3 (odd) → 3 − 1 = 2

5 (odd) → 5 − 1 = 4

2 (even) → 2 + 2 = 4

9 (odd) → 9 − 1 = 8

6 (even) → 6 + 2 = 8

New number: 66042488

Digits appearing more than once: 6, 4, 8

So, Three digits will appear more than once in the new number thus formed.

Thus, correct option is (c).