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If 2 is added to each even digit and 1 is subtracted from each odd digit in the number 2614759, what will be the sum of the digits which are sixt
Question

If 2 is added to each even digit and 1 is subtracted from each odd digit in the number 2614759, what will be the sum of the digits which are sixth from the left and first from the right in the new number thus formed?​

A.

10

B.

14

C.

12

D.

6

Correct option is C

Given: 2614759
Logic: Add 2 to even digits and Subtract 1 from odd digits
2 → even → 2 + 2 = 4
6 → even → 6 + 2 = 8
1 → odd → 1 - 1 = 0
4 → even → 4 + 2 = 6
7 → odd → 7 - 1 = 6
5 → odd → 5 - 1 = 4
9 → odd → 9 - 1 = 8
New number = 4806648
6th from left = 4
1st from right = 8
Sum = 4 + 8 = 12
Thus, the correct option is (c).

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