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If (2.1×2.1)−(2×a×2.1)+(0.6×0.6)=(1.5)2(2.1× 2.1)-(2×a×2.1)+ (0.6×0.6)={(1.5)}^2(2.1×2.1)−(2×a×2.1)+(0.6×0.6)=(1.5)2​, then find the value of a.
Question

If (2.1×2.1)(2×a×2.1)+(0.6×0.6)=(1.5)2(2.1× 2.1)-(2×a×2.1)+ (0.6×0.6)={(1.5)}^2​, then find the value of a.

A.

0.6

B.

2.1

C.

0.62

D.

1.5

Correct option is A

Given:

(2.1×2.1)(2×a×2.1)+(0.6×0.6)=1.52(2.1 \times 2.1) - (2 \times a \times 2.1) + (0.6 \times 0.6) = 1.5^2 ​​

Solution:

2.1×2.1=4.41,2×a×2.1=4.2a,0.6×0.6=0.36,1.52=2.252.1 \times 2.1 = 4.41, \quad 2 \times a \times 2.1 = 4.2a, \quad 0.6 \times 0.6 = 0.36, \quad 1.5^2 = 2.25 

Now, expression becomes

4.414.2a+0.36=2.25 4.774.2a=2.25 4.2a=2.254.77=2.52 a=2.524.2=0.64.41 - 4.2a + 0.36 = 2.25 \\ \ \\ 4.77−4.2a=2.25 \\ \ \\ -4.2a = 2.25 - 4.77 = -2.52 \\ \ \\ a = \frac{-2.52}{-4.2} = 0.6 ​​

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