If 11 August 2004 is Wednesday, then what will be the day of the week on 11 February 2006?
11 August 2004 was Wednesday.
Then, 11 August 2005 was Wednesday + 1 = Thursday.
Calculate total number of days between 11 August 2005 and 11 February 2006
= 20 + 30 + 31 + 30 + 31+ 31 + 11 = 184 days.
Number of odd days= 184/7 = 2 odd days.
So, the day on 11 February 2006 will be = Thursday + 2 = Saturday.
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