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    If 1 is subtracted from each odd digit and 2 is added to each even digit in the number '6472311', what will be the sum of the digits that are second f
    Question

    If 1 is subtracted from each odd digit and 2 is added to each even digit in the number '6472311', what will be the sum of the digits that are second from the left and second from the right in the new number thus formed?

    A.

    8

    B.

    6

    C.

    7

    D.

    9

    Correct option is B

    Given: 6472311
    Subtract 1 from each odd digit:
    7 - 1 = 6; 3 - 1 = 2; 1 - 1 = 0; 1 - 1 = 0
    Add 2 to each even digit:
    6 + 2 = 8; 4 + 2 = 6; 2 + 2 = 4
    So, the number formed is '8664200'.
    The digit that is second from the left = 6, and second from the right = 0
    Sum = 6 + 0 = 6
    Thus, the correct answer is (b).

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