If 1 is added to each odd digit and 1 is subtracted from each even digit in the number 7873262, what will be the sum of the digits that are third and fourth from the left in the new number thus formed?

Given the number: 7 8 7 3 2 6 2
The rule is:
Add 1 to each odd digit.
Subtract 1 from each even digit.
Apply this to each digit:
7 is odd, so 7 + 1 = 8
8 is even, so 8 - 1 = 7
7 is odd, so 7 + 1 = 8
3 is odd, so 3 + 1 = 4
2 is even, so 2 - 1 = 1
6 is even, so 6 - 1 = 5
2 is even, so 2 - 1 = 1
So, the new number formed is: 8 7 8 4 1 5 1
The third digit from the left is 8, and the fourth digit is 4. Their sum is 8 + 4 = 12.

Correct answer is (a) 12.