If 1 is added to each even digit and 2 is subtracted from each odd digit in the number 72384596, how many digits will appear more than once in the new number thus formed?​

Given: 72384596

Add 1 to each even digit and subtract 2 from each odd digit.

7 (odd) → 7 − 2 = 5

2 (even) → 2 + 1 = 3

3 (odd) → 3 − 2 = 1

8 (even) → 8 + 1 = 9

4 (even) → 4 + 1 = 5

5 (odd) → 5 − 2 = 3

9 (odd) → 9 − 2 = 7

6 (even) → 6 + 1 = 7

New number formed: 5, 3, 1, 9, 5, 3, 7, 7

Digits appearing more than once:

5, 3, 7 → Total = 3 digits

So, three digits will appear more than once in the new number thus formed.

Thus, correct option is (c).