If 1 is added to each even digit and 1 is subtracted from each odd digit in the number 7521432, what will be the sum of digits which are second from left and third from right in the new number thus formed?​

Given: 7521432

Add 1 to each even digit and subtract 1 from each odd digit.

7 (odd) → 7 − 1 = 6

5 (odd) → 5 − 1 = 4

2 (even) → 2 + 1 = 3

1 (odd) → 1 − 1 = 0

4 (even) → 4 + 1 = 5

3 (odd) → 3 − 1 = 2

2 (even) → 2 + 1 = 3

New formed number: 6, 4, 3, 0, 5, 2, 3

Second from the left = 4

Third from the right = 5

Add: 4 + 5 = 9

So, 9 will be the sum of digits which are second from left and third from right in the new number thus formed.

Thus, correct option is (a).