​If 1 is added for each even digit and 1 is subtracted from each odd digit of the number 56218643, how many digits are repeated more than once in the new number thus formed?

Given: 56218643

If 1 is added for each even digit and 1 is subtracted from each odd digit of the number.

5 (odd) → 5 − 1 = 4

6 (even) → 6 + 1 = 7

2 (even) → 2 + 1 = 3

1 (odd) → 1 − 1 = 0

8 (even) → 8 + 1 = 9

6 (even) → 6 + 1 = 7

4 (even) → 4 + 1 = 5

3 (odd) → 3 − 1 = 2

New number = 4 7 3 0 9 7 5 2

Repeat digit: 7

So, one digits are repeated more than once in the new number thus formed.

Thus, correct option is (c).