Correct option is E
I. 5x² + 7x – 90 = 0
5x² + 25x – 18x – 90 = 0
5x (x + 5) – 18 (x + 5)= 0
(x + 5) (5x – 18) = 0
x=-5,18/5
II. 3y² + 28y + 64 = 0
3y² + 12y + 16y + 64 = 0
3y (y + 4) + 16 (y + 4) = 0
I. 5x² + 7x – 90 = 0
5x² + 25x – 18x – 90 = 0
5x (x + 5) – 18 (x + 5)= 0
(x + 5) (5x – 18) = 0
x=-5,18/5
II. 3y² + 28y + 64 = 0
3y² + 12y + 16y + 64 = 0
3y (y + 4) + 16 (y + 4) = 0
(3y + 16) (y +4) = 0
y = -16/3, -4
y = -16/3, -4
| Values | (x) | (y) | Relation |
| 1 | 18/5 | -4 | (x > y) |
| 2 | 18/5 | -16/3 | (x > y) |
| 3 | -5 | -4 | (x < y) |
| 4 | -5 | -16/3 | (x > y) |
No relation can be established between x & y
English
100 Questions
100 Marks
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