In the following question, two equations are given. Solve these equations, and answer the question given below. 

I. 2x² + 13x + 20 = 0
II. 3y² + 26y + 56 = 0

Correct option is B

I. 2x² + 13x + 20 = 0
2x² + 8x + 5x + 20 = 0
2x(x + 4) + 5 (x + 4) = 0
(2x + 5) (x + 4) = 0
x=(-5)/2,-4
II. 3y² + 26y +56 = 0
3y² + 12y + 14y + 56 = 0
3y (y + 4) + 14 (y + 4) = 0
(3y + 14) (y + 4) =0
y= -14/3,-4
x ≥ y