​How many sides will a polygon have if the sum of the measures of its interior angles is 900°?​

Correct option is A

Given:

Sum of interior angles = $$900^o$$​​

Formula Used:

Sum of interior angles of polygon with side n =$$(n-2) \times 180^o$$​​

Solution:

For the sum of $$900^o$$​​

​$$(n-2) \times 180^o = 900^o$$​​

​$$(n-2) = \frac{900}{180} =5$$​​

n = 5+2 = 7