How many numbers between 1 and 700 are completely divisible by 17?

Correct option is D

Given:
Numbers 1 to 700
Formula Used:
Last Term($$a_n$$​) = First Term(a)+ (Number of terms(n) - 1) × Common Difference(d)

​​Solution:

We know a=17 and d=17
Sequence: 17, 34, 51,…,697, where the last term l=697
$$a_n$$​=697, a=17, and d=17
697=17+(n-1)⋅17
697-17=(n-1)⋅17
680=(n-1)⋅17
n-1= $$\frac{680}{17}$$​​
n-1=40
n= 41